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111413112103 = 210761528623
BaseRepresentation
bin110011111000010111…
…1010010110100100111
3101122120120102111202101
41213300233102310213
53311133224041403
6123103225352531
711022630553546
oct1476057226447
9348516374671
10111413112103
1143282885157
1219714038747
13a6771b9907
14556cb4a15d
152d711cc71d
hex19f0bd2d27

111413112103 has 4 divisors (see below), whose sum is σ = 111413851488. Its totient is φ = 111412372720.

The previous prime is 111413112091. The next prime is 111413112131. The reversal of 111413112103 is 301211314111.

It is a semiprime because it is the product of two primes, and also a brilliant number, because the two primes have the same length.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-111413112103 is a prime.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (111413112163) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 53551 + ... + 475072.

It is an arithmetic number, because the mean of its divisors is an integer number (27853462872).

Almost surely, 2111413112103 is an apocalyptic number.

111413112103 is a deficient number, since it is larger than the sum of its proper divisors (739385).

111413112103 is an equidigital number, since it uses as much as digits as its factorization.

111413112103 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 739384.

The product of its (nonzero) digits is 72, while the sum is 19.

Adding to 111413112103 its reverse (301211314111), we get a palindrome (412624426214).

The spelling of 111413112103 in words is "one hundred eleven billion, four hundred thirteen million, one hundred twelve thousand, one hundred three".

Divisors: 1 210761 528623 111413112103