Base | Representation |
---|---|
bin | 110011111000010111… |
… | …1010010110101000011 |
3 | 101122120120102111210102 |
4 | 1213300233102311003 |
5 | 3311133224042011 |
6 | 123103225353015 |
7 | 11022630553616 |
oct | 1476057226503 |
9 | 348516374712 |
10 | 111413112131 |
11 | 43282885182 |
12 | 1971403876b |
13 | a6771b9929 |
14 | 556cb4a17d |
15 | 2d711cc73b |
hex | 19f0bd2d43 |
111413112131 has 2 divisors, whose sum is σ = 111413112132. Its totient is φ = 111413112130.
The previous prime is 111413112091. The next prime is 111413112163. The reversal of 111413112131 is 131211314111.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 111413112131 - 218 = 111412849987 is a prime.
It is a super-2 number, since 2×1114131121312 (a number of 23 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (111413117131) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 55706556065 + 55706556066.
It is an arithmetic number, because the mean of its divisors is an integer number (55706556066).
Almost surely, 2111413112131 is an apocalyptic number.
111413112131 is a deficient number, since it is larger than the sum of its proper divisors (1).
111413112131 is an equidigital number, since it uses as much as digits as its factorization.
111413112131 is an evil number, because the sum of its binary digits is even.
The product of its digits is 72, while the sum is 20.
Adding to 111413112131 its reverse (131211314111), we get a palindrome (242624426242).
The spelling of 111413112131 in words is "one hundred eleven billion, four hundred thirteen million, one hundred twelve thousand, one hundred thirty-one".
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