Base | Representation |
---|---|
bin | 10000001101100111100… |
… | …001010111110101101011 |
3 | 10221111202212102101110211 |
4 | 100031213201113311223 |
5 | 121223221113100212 |
6 | 2211454211521551 |
7 | 143331156030043 |
oct | 20154741276553 |
9 | 3844685371424 |
10 | 1114133331307 |
11 | 39a557246a97 |
12 | 15bb14bb92b7 |
13 | 810a6bcacc9 |
14 | 3bcd256a723 |
15 | 1deab66e9a7 |
hex | 10367857d6b |
1114133331307 has 2 divisors, whose sum is σ = 1114133331308. Its totient is φ = 1114133331306.
The previous prime is 1114133331287. The next prime is 1114133331313. The reversal of 1114133331307 is 7031333314111.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 1114133331307 - 231 = 1111985847659 is a prime.
It is not a weakly prime, because it can be changed into another prime (1114133331607) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 557066665653 + 557066665654.
It is an arithmetic number, because the mean of its divisors is an integer number (557066665654).
Almost surely, 21114133331307 is an apocalyptic number.
1114133331307 is a deficient number, since it is larger than the sum of its proper divisors (1).
1114133331307 is an equidigital number, since it uses as much as digits as its factorization.
1114133331307 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 6804, while the sum is 31.
Adding to 1114133331307 its reverse (7031333314111), we get a palindrome (8145466645418).
The spelling of 1114133331307 in words is "one trillion, one hundred fourteen billion, one hundred thirty-three million, three hundred thirty-one thousand, three hundred seven".
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