Search a number
-
+
111414055513 is a prime number
BaseRepresentation
bin110011111000011001…
…0111001001001011001
3101122120122012102212111
41213300302321021121
53311133444234023
6123103301512321
711022641563165
oct1476062711131
9348518172774
10111414055513
1143283369a32
12197144126a1
13a67745a147
14556cd13ca5
152d7131700d
hex19f0cb9259

111414055513 has 2 divisors, whose sum is σ = 111414055514. Its totient is φ = 111414055512.

The previous prime is 111414055499. The next prime is 111414055553. The reversal of 111414055513 is 315550414111.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 107706706969 + 3707348544 = 328187^2 + 60888^2 .

It is a cyclic number.

It is not a de Polignac number, because 111414055513 - 25 = 111414055481 is a prime.

It is not a weakly prime, because it can be changed into another prime (111414055553) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 55707027756 + 55707027757.

It is an arithmetic number, because the mean of its divisors is an integer number (55707027757).

Almost surely, 2111414055513 is an apocalyptic number.

It is an amenable number.

111414055513 is a deficient number, since it is larger than the sum of its proper divisors (1).

111414055513 is an equidigital number, since it uses as much as digits as its factorization.

111414055513 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 6000, while the sum is 31.

Adding to 111414055513 its reverse (315550414111), we get a palindrome (426964469624).

The spelling of 111414055513 in words is "one hundred eleven billion, four hundred fourteen million, fifty-five thousand, five hundred thirteen".