Base | Representation |
---|---|
bin | 110011111000011001… |
… | …0111001001001011001 |
3 | 101122120122012102212111 |
4 | 1213300302321021121 |
5 | 3311133444234023 |
6 | 123103301512321 |
7 | 11022641563165 |
oct | 1476062711131 |
9 | 348518172774 |
10 | 111414055513 |
11 | 43283369a32 |
12 | 197144126a1 |
13 | a67745a147 |
14 | 556cd13ca5 |
15 | 2d7131700d |
hex | 19f0cb9259 |
111414055513 has 2 divisors, whose sum is σ = 111414055514. Its totient is φ = 111414055512.
The previous prime is 111414055499. The next prime is 111414055553. The reversal of 111414055513 is 315550414111.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 107706706969 + 3707348544 = 328187^2 + 60888^2 .
It is a cyclic number.
It is not a de Polignac number, because 111414055513 - 25 = 111414055481 is a prime.
It is not a weakly prime, because it can be changed into another prime (111414055553) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 55707027756 + 55707027757.
It is an arithmetic number, because the mean of its divisors is an integer number (55707027757).
Almost surely, 2111414055513 is an apocalyptic number.
It is an amenable number.
111414055513 is a deficient number, since it is larger than the sum of its proper divisors (1).
111414055513 is an equidigital number, since it uses as much as digits as its factorization.
111414055513 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 6000, while the sum is 31.
Adding to 111414055513 its reverse (315550414111), we get a palindrome (426964469624).
The spelling of 111414055513 in words is "one hundred eleven billion, four hundred fourteen million, fifty-five thousand, five hundred thirteen".
• e-mail: info -at- numbersaplenty.com • Privacy notice • done in 0.069 sec. • engine limits •