Base | Representation |
---|---|
bin | 10100110000001010… |
… | …10000110111000011 |
3 | 1001202110121100210212 |
4 | 22120011100313003 |
5 | 140304202414303 |
6 | 5041315544335 |
7 | 543044526011 |
oct | 123005206703 |
9 | 31673540725 |
10 | 11141451203 |
11 | 47a8071213 |
12 | 21ab2bb0ab |
13 | 108732239c |
14 | 7799b18b1 |
15 | 4531d0ad8 |
hex | 298150dc3 |
11141451203 has 2 divisors, whose sum is σ = 11141451204. Its totient is φ = 11141451202.
The previous prime is 11141451161. The next prime is 11141451247. The reversal of 11141451203 is 30215414111.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 11141451203 - 214 = 11141434819 is a prime.
It is not a weakly prime, because it can be changed into another prime (11141457203) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5570725601 + 5570725602.
It is an arithmetic number, because the mean of its divisors is an integer number (5570725602).
Almost surely, 211141451203 is an apocalyptic number.
11141451203 is a deficient number, since it is larger than the sum of its proper divisors (1).
11141451203 is an equidigital number, since it uses as much as digits as its factorization.
11141451203 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 480, while the sum is 23.
Adding to 11141451203 its reverse (30215414111), we get a palindrome (41356865314).
The spelling of 11141451203 in words is "eleven billion, one hundred forty-one million, four hundred fifty-one thousand, two hundred three".
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