Base | Representation |
---|---|
bin | 10000001101101011100… |
… | …000000100110100011001 |
3 | 10221111221112001121001212 |
4 | 100031223200010310121 |
5 | 121223340211200441 |
6 | 2211504554552505 |
7 | 143332626405233 |
oct | 20155340046431 |
9 | 3844845047055 |
10 | 1114200100121 |
11 | 39a590a00429 |
12 | 15bb33438735 |
13 | 810b79a7b94 |
14 | 3bcdb38b253 |
15 | 1deb245ceeb |
hex | 1036b804d19 |
1114200100121 has 2 divisors, whose sum is σ = 1114200100122. Its totient is φ = 1114200100120.
The previous prime is 1114200100067. The next prime is 1114200100133. The reversal of 1114200100121 is 1210010024111.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 1056198121225 + 58001978896 = 1027715^2 + 240836^2 .
It is a cyclic number.
It is not a de Polignac number, because 1114200100121 - 230 = 1113126358297 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 1114200100096 and 1114200100105.
It is not a weakly prime, because it can be changed into another prime (1114200150121) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 557100050060 + 557100050061.
It is an arithmetic number, because the mean of its divisors is an integer number (557100050061).
Almost surely, 21114200100121 is an apocalyptic number.
It is an amenable number.
1114200100121 is a deficient number, since it is larger than the sum of its proper divisors (1).
1114200100121 is an equidigital number, since it uses as much as digits as its factorization.
1114200100121 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 16, while the sum is 14.
Adding to 1114200100121 its reverse (1210010024111), we get a palindrome (2324210124232).
The spelling of 1114200100121 in words is "one trillion, one hundred fourteen billion, two hundred million, one hundred thousand, one hundred twenty-one".
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