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1114200111403 = 4767397891251
BaseRepresentation
bin10000001101101011100…
…000000111100100101011
310221111221112002011112201
4100031223200013210223
5121223340212031103
62211504555121031
7143332626453151
oct20155340074453
93844845064481
101114200111403
1139a590a08955
1215bb33443177
13810b79b0062
143bcdb3913d1
151deb246151d
hex1036b80792b

1114200111403 has 16 divisors (see below), whose sum is σ = 1157800518144. Its totient is φ = 1071510660000.

The previous prime is 1114200111329. The next prime is 1114200111407. The reversal of 1114200111403 is 3041110024111.

It is a cyclic number.

It is not a de Polignac number, because 1114200111403 - 217 = 1114199980331 is a prime.

It is a super-2 number, since 2×11142001114032 (a number of 25 digits) contains 22 as substring.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (1114200111407) by changing a digit.

It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 804528 + ... + 1695778.

It is an arithmetic number, because the mean of its divisors is an integer number (72362532384).

Almost surely, 21114200111403 is an apocalyptic number.

1114200111403 is a deficient number, since it is larger than the sum of its proper divisors (43600406741).

1114200111403 is an equidigital number, since it uses as much as digits as its factorization.

1114200111403 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 891762.

The product of its (nonzero) digits is 96, while the sum is 19.

Adding to 1114200111403 its reverse (3041110024111), we get a palindrome (4155310135514).

The spelling of 1114200111403 in words is "one trillion, one hundred fourteen billion, two hundred million, one hundred eleven thousand, four hundred three".

Divisors: 1 47 67 397 3149 18659 26599 891251 1250153 41888797 59713817 353826647 2806549399 16629852409 23706385349 1114200111403