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11142100141 = 25303440347
BaseRepresentation
bin10100110000001111…
…01111010010101101
31001202111211022222121
422120013233102231
5140304334201031
65041341512541
7543053200654
oct123007572255
931674738877
1011142100141
1147a8474827
1221ab572751
1310874bb883
14779b0019b
154532ad011
hex2981ef4ad

11142100141 has 4 divisors (see below), whose sum is σ = 11142565792. Its totient is φ = 11141634492.

The previous prime is 11142100127. The next prime is 11142100153. The reversal of 11142100141 is 14100124111.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4, and also an emirpimes, since its reverse is a distinct semiprime: 14100124111 = 40073518873.

It is a cyclic number.

It is not a de Polignac number, because 11142100141 - 215 = 11142067373 is a prime.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (11142190141) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 194871 + ... + 245476.

It is an arithmetic number, because the mean of its divisors is an integer number (2785641448).

Almost surely, 211142100141 is an apocalyptic number.

It is an amenable number.

11142100141 is a deficient number, since it is larger than the sum of its proper divisors (465651).

11142100141 is an equidigital number, since it uses as much as digits as its factorization.

11142100141 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 465650.

The product of its (nonzero) digits is 32, while the sum is 16.

Adding to 11142100141 its reverse (14100124111), we get a palindrome (25242224252).

The spelling of 11142100141 in words is "eleven billion, one hundred forty-two million, one hundred thousand, one hundred forty-one".

Divisors: 1 25303 440347 11142100141