111421303102431 has 96 divisors (see below), whose sum is σ = 195973537518720. Its totient is φ = 59549585743872.

The previous prime is 111421303102429. The next prime is 111421303102433. The reversal of 111421303102431 is 134201303124111.

111421303102431 is a `hidden beast` number, since 1 + 1 + 1 + 4 + 213 + 0 + 3 + 10 + 2 + 431 = 666.

It is an interprime number because it is at equal distance from previous prime (111421303102429) and next prime (111421303102433).

It is not a de Polignac number, because 111421303102431 - 2¹ = 111421303102429 is a prime.

It is a super-2 number, since 2×111421303102431² (a number of 29 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 111421303102395 and 111421303102404.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (111421303102433) by changing a digit.

It is a polite number, since it can be written in 95 ways as a sum of consecutive naturals, for example, 126578781 + ... + 127455993.

It is an arithmetic number, because the mean of its divisors is an integer number (2041391015820).

Almost surely, 2^{111421303102431} is an apocalyptic number.

111421303102431 is a deficient number, since it is larger than the sum of its proper divisors (84552234416289).

111421303102431 is a wasteful number, since it uses less digits than its factorization.

111421303102431 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 877985 (or 877982 counting only the distinct ones).

The product of its (nonzero) digits is 1728, while the sum is 27.

Adding to 111421303102431 its reverse (134201303124111), we get a palindrome (245622606226542).

The spelling of 111421303102431 in words is "one hundred eleven trillion, four hundred twenty-one billion, three hundred three million, one hundred two thousand, four hundred thirty-one".