Base | Representation |
---|---|
bin | 1010001000100100000101… |
… | …1101111100100010111011 |
3 | 1110110012002002221221112210 |
4 | 2202021001131330202323 |
5 | 2430023303321110120 |
6 | 35410402004110203 |
7 | 2230000116242154 |
oct | 242110135744273 |
9 | 43405062857483 |
10 | 11142243535035 |
11 | 3606442aa8138 |
12 | 12bb536995363 |
13 | 62a92aa4b272 |
14 | 2a7404b3492b |
15 | 144c7e346ce0 |
hex | a224177c8bb |
11142243535035 has 64 divisors (see below), whose sum is σ = 19246583301120. Its totient is φ = 5486962291200.
The previous prime is 11142243535013. The next prime is 11142243535051. The reversal of 11142243535035 is 53053534224111.
It is not a de Polignac number, because 11142243535035 - 212 = 11142243530939 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 11142243534984 and 11142243535002.
It is an unprimeable number.
It is a polite number, since it can be written in 63 ways as a sum of consecutive naturals, for example, 161704 + ... + 4723413.
It is an arithmetic number, because the mean of its divisors is an integer number (300727864080).
Almost surely, 211142243535035 is an apocalyptic number.
11142243535035 is a gapful number since it is divisible by the number (15) formed by its first and last digit.
11142243535035 is a deficient number, since it is larger than the sum of its proper divisors (8104339766085).
11142243535035 is a wasteful number, since it uses less digits than its factorization.
11142243535035 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 4885348.
The product of its (nonzero) digits is 216000, while the sum is 39.
Adding to 11142243535035 its reverse (53053534224111), we get a palindrome (64195777759146).
The spelling of 11142243535035 in words is "eleven trillion, one hundred forty-two billion, two hundred forty-three million, five hundred thirty-five thousand, thirty-five".
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