1114255433 has 2 divisors, whose sum is σ = 1114255434. Its totient is φ = 1114255432.

The previous prime is 1114255423. The next prime is 1114255501. The reversal of 1114255433 is 3345524111.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 1068178489 + 46076944 = 32683^2 + 6788^2 .

It is a cyclic number.

It is not a de Polignac number, because 1114255433 - 2⁶ = 1114255369 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 1114255396 and 1114255405.

It is not a weakly prime, because it can be changed into another prime (1114255423) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (11) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 557127716 + 557127717.

It is an arithmetic number, because the mean of its divisors is an integer number (557127717).

Almost surely, 2^1114255433 is an apocalyptic number.

It is an amenable number.

1114255433 is a deficient number, since it is larger than the sum of its proper divisors (1).

1114255433 is an equidigital number, since it uses as much as digits as its factorization.

1114255433 is an odious number, because the sum of its binary digits is odd.

The product of its digits is 7200, while the sum is 29.

The square root of 1114255433 is about 33380.4648409815. The cubic root of 1114255433 is about 1036.7202624018.

Adding to 1114255433 its reverse (3345524111), we get a palindrome (4459779544).

The spelling of 1114255433 in words is "one billion, one hundred fourteen million, two hundred fifty-five thousand, four hundred thirty-three".