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11143052133 = 329128081059
BaseRepresentation
bin10100110000010110…
…10111101101100101
31001202120121200212120
422120023113231211
5140310110132013
65041414140153
7543064244313
oct123013275545
931676550776
1011143052133
1147a8a64aa4
1221ab951659
131087762c95
14779cab0b3
154533ea123
hex2982d7b65

11143052133 has 8 divisors (see below), whose sum is σ = 15369727200. Its totient is φ = 7172539248.

The previous prime is 11143052131. The next prime is 11143052251. The reversal of 11143052133 is 33125034111.

It is a sphenic number, since it is the product of 3 distinct primes.

It is not a de Polignac number, because 11143052133 - 21 = 11143052131 is a prime.

It is a super-2 number, since 2×111430521332 (a number of 21 digits) contains 22 as substring.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (11143052131) by changing a digit.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 64040443 + ... + 64040616.

It is an arithmetic number, because the mean of its divisors is an integer number (1921215900).

Almost surely, 211143052133 is an apocalyptic number.

It is an amenable number.

11143052133 is a deficient number, since it is larger than the sum of its proper divisors (4226675067).

11143052133 is a wasteful number, since it uses less digits than its factorization.

11143052133 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 128081091.

The product of its (nonzero) digits is 1080, while the sum is 24.

Adding to 11143052133 its reverse (33125034111), we get a palindrome (44268086244).

The spelling of 11143052133 in words is "eleven billion, one hundred forty-three million, fifty-two thousand, one hundred thirty-three".

Divisors: 1 3 29 87 128081059 384243177 3714350711 11143052133