Base | Representation |
---|---|
bin | 1010001000100111011010… |
… | …0010111011010100110011 |
3 | 1110110021101011120221101102 |
4 | 2202021312202323110303 |
5 | 2430032114303030303 |
6 | 35411030214355015 |
7 | 2230031151324554 |
oct | 242116642732463 |
9 | 43407334527342 |
10 | 11143134033203 |
11 | 360685a72a637 |
12 | 12bb74505ba6b |
13 | 62aa40398a63 |
14 | 2a748b0da32b |
15 | 144cd25e8288 |
hex | a22768bb533 |
11143134033203 has 2 divisors, whose sum is σ = 11143134033204. Its totient is φ = 11143134033202.
The previous prime is 11143134033181. The next prime is 11143134033253. The reversal of 11143134033203 is 30233043134111.
11143134033203 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 11143134033203 - 242 = 6745087522099 is a prime.
It is not a weakly prime, because it can be changed into another prime (11143134033253) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5571567016601 + 5571567016602.
It is an arithmetic number, because the mean of its divisors is an integer number (5571567016602).
Almost surely, 211143134033203 is an apocalyptic number.
11143134033203 is a deficient number, since it is larger than the sum of its proper divisors (1).
11143134033203 is an equidigital number, since it uses as much as digits as its factorization.
11143134033203 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 7776, while the sum is 29.
Adding to 11143134033203 its reverse (30233043134111), we get a palindrome (41376177167314).
The spelling of 11143134033203 in words is "eleven trillion, one hundred forty-three billion, one hundred thirty-four million, thirty-three thousand, two hundred three".
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