Base | Representation |
---|---|
bin | 10100110000010111… |
… | …01101011101011110 |
3 | 1001202120210020001212 |
4 | 22120023231131132 |
5 | 140310121004324 |
6 | 5041420104422 |
7 | 543065065112 |
oct | 123013553536 |
9 | 31676706055 |
10 | 11143141214 |
11 | 47a9015a17 |
12 | 21ab995112 |
13 | 10877946aa |
14 | 779cd1742 |
15 | 45341670e |
hex | 2982ed75e |
11143141214 has 4 divisors (see below), whose sum is σ = 16714711824. Its totient is φ = 5571570606.
The previous prime is 11143141201. The next prime is 11143141271. The reversal of 11143141214 is 41214134111.
It is a semiprime because it is the product of two primes, and also an emirpimes, since its reverse is a distinct semiprime: 41214134111 = 182887 ⋅225353.
It is a super-2 number, since 2×111431412142 (a number of 21 digits) contains 22 as substring.
It is a self number, because there is not a number n which added to its sum of digits gives 11143141214.
It is a congruent number.
It is an unprimeable number.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2785785302 + ... + 2785785305.
It is an arithmetic number, because the mean of its divisors is an integer number (4178677956).
Almost surely, 211143141214 is an apocalyptic number.
11143141214 is a deficient number, since it is larger than the sum of its proper divisors (5571570610).
11143141214 is an equidigital number, since it uses as much as digits as its factorization.
11143141214 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 5571570609.
The product of its digits is 384, while the sum is 23.
Adding to 11143141214 its reverse (41214134111), we get a palindrome (52357275325).
The spelling of 11143141214 in words is "eleven billion, one hundred forty-three million, one hundred forty-one thousand, two hundred fourteen".
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