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11143214353 is a prime number
BaseRepresentation
bin10100110000010111…
…11111010100010001
31001202120220221101201
422120023333110101
5140310130324403
65041421431201
7543065521255
oct123013772421
931676827351
1011143214353
1147a9065967
1221aba0b501
1310877bba7b
14779d10265
1545342d21d
hex2982ff511

11143214353 has 2 divisors, whose sum is σ = 11143214354. Its totient is φ = 11143214352.

The previous prime is 11143214323. The next prime is 11143214387. The reversal of 11143214353 is 35341234111.

11143214353 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 6749115409 + 4394098944 = 82153^2 + 66288^2 .

It is a cyclic number.

It is not a de Polignac number, because 11143214353 - 25 = 11143214321 is a prime.

It is a super-2 number, since 2×111432143532 (a number of 21 digits) contains 22 as substring.

It is not a weakly prime, because it can be changed into another prime (11143214323) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5571607176 + 5571607177.

It is an arithmetic number, because the mean of its divisors is an integer number (5571607177).

Almost surely, 211143214353 is an apocalyptic number.

It is an amenable number.

11143214353 is a deficient number, since it is larger than the sum of its proper divisors (1).

11143214353 is an equidigital number, since it uses as much as digits as its factorization.

11143214353 is an odious number, because the sum of its binary digits is odd.

The product of its digits is 4320, while the sum is 28.

Adding to 11143214353 its reverse (35341234111), we get a palindrome (46484448464).

The spelling of 11143214353 in words is "eleven billion, one hundred forty-three million, two hundred fourteen thousand, three hundred fifty-three".