Base | Representation |
---|---|
bin | 10100110000011000… |
… | …10101101101110011 |
3 | 1001202121002121020201 |
4 | 22120030111231303 |
5 | 140310141243344 |
6 | 5041423420031 |
7 | 543066352612 |
oct | 123014255563 |
9 | 31677077221 |
10 | 11143306099 |
11 | 47a9118892 |
12 | 21aba54617 |
13 | 1087821763 |
14 | 779d35879 |
15 | 45344a4d4 |
hex | 298315b73 |
11143306099 has 2 divisors, whose sum is σ = 11143306100. Its totient is φ = 11143306098.
The previous prime is 11143306051. The next prime is 11143306103. The reversal of 11143306099 is 99060334111.
11143306099 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 11143306099 - 217 = 11143175027 is a prime.
It is not a weakly prime, because it can be changed into another prime (11143306019) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (17) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5571653049 + 5571653050.
It is an arithmetic number, because the mean of its divisors is an integer number (5571653050).
Almost surely, 211143306099 is an apocalyptic number.
11143306099 is a deficient number, since it is larger than the sum of its proper divisors (1).
11143306099 is an equidigital number, since it uses as much as digits as its factorization.
11143306099 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 17496, while the sum is 37.
The spelling of 11143306099 in words is "eleven billion, one hundred forty-three million, three hundred six thousand, ninety-nine".
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