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11143310302 = 25571655151
BaseRepresentation
bin10100110000011000…
…10110101111011110
31001202121002211000101
422120030112233132
5140310141412202
65041423451314
7543066401065
oct123014265736
931677084011
1011143310302
1147a9120a63
1221aba56b3a
131087823647
14779d371dc
1545344b887
hex298316bde

11143310302 has 4 divisors (see below), whose sum is σ = 16714965456. Its totient is φ = 5571655150.

The previous prime is 11143310279. The next prime is 11143310329. The reversal of 11143310302 is 20301334111.

It is a semiprime because it is the product of two primes, and also an emirpimes, since its reverse is a distinct semiprime: 20301334111 = 191068491269.

It is a self number, because there is not a number n which added to its sum of digits gives 11143310302.

It is a congruent number.

It is an unprimeable number.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2785827574 + ... + 2785827577.

It is an arithmetic number, because the mean of its divisors is an integer number (4178741364).

Almost surely, 211143310302 is an apocalyptic number.

11143310302 is a deficient number, since it is larger than the sum of its proper divisors (5571655154).

11143310302 is an equidigital number, since it uses as much as digits as its factorization.

11143310302 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 5571655153.

The product of its (nonzero) digits is 216, while the sum is 19.

Adding to 11143310302 its reverse (20301334111), we get a palindrome (31444644413).

The spelling of 11143310302 in words is "eleven billion, one hundred forty-three million, three hundred ten thousand, three hundred two".

Divisors: 1 2 5571655151 11143310302