11143311131 has 2 divisors, whose sum is σ = 11143311132. Its totient is φ = 11143311130.

The previous prime is 11143311071. The next prime is 11143311139. The reversal of 11143311131 is 13111334111.

11143311131 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a strong prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-11143311131 is a prime.

It is a super-2 number, since 2×11143311131² (a number of 21 digits) contains 22 as substring.

It is not a weakly prime, because it can be changed into another prime (11143311139) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5571655565 + 5571655566.

It is an arithmetic number, because the mean of its divisors is an integer number (5571655566).

Almost surely, 2^11143311131 is an apocalyptic number.

11143311131 is a deficient number, since it is larger than the sum of its proper divisors (1).

11143311131 is an equidigital number, since it uses as much as digits as its factorization.

11143311131 is an odious number, because the sum of its binary digits is odd.

The product of its digits is 108, while the sum is 20.

Adding to 11143311131 its reverse (13111334111), we get a palindrome (24254645242).

The spelling of 11143311131 in words is "eleven billion, one hundred forty-three million, three hundred eleven thousand, one hundred thirty-one".