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1114340314232 = 23891565084711
BaseRepresentation
bin10000001101110011110…
…110111100110001111000
310221112022021220012200002
4100031303312330301320
5121224132110023412
62211530524132132
7143336251246565
oct20156366746170
93845267805602
101114340314232
1139a653069362
1215bb72397048
138110aa5b802
143bd11c4986c
151debe907dc2
hex10373dbcc78

1114340314232 has 16 divisors (see below), whose sum is σ = 2112864361200. Its totient is φ = 550909817920.

The previous prime is 1114340314211. The next prime is 1114340314379. The reversal of 1114340314232 is 2324130434111.

It is a super-3 number, since 3×11143403142323 (a number of 37 digits) contains 333 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 1114340314195 and 1114340314204.

It is a congruent number.

It is an unprimeable number.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 782541644 + ... + 782543067.

It is an arithmetic number, because the mean of its divisors is an integer number (132054022575).

Almost surely, 21114340314232 is an apocalyptic number.

It is an amenable number.

1114340314232 is a deficient number, since it is larger than the sum of its proper divisors (998524046968).

1114340314232 is a wasteful number, since it uses less digits than its factorization.

1114340314232 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 1565084806 (or 1565084802 counting only the distinct ones).

The product of its (nonzero) digits is 6912, while the sum is 29.

Adding to 1114340314232 its reverse (2324130434111), we get a palindrome (3438470748343).

The spelling of 1114340314232 in words is "one trillion, one hundred fourteen billion, three hundred forty million, three hundred fourteen thousand, two hundred thirty-two".

Divisors: 1 2 4 8 89 178 356 712 1565084711 3130169422 6260338844 12520677688 139292539279 278585078558 557170157116 1114340314232