Base | Representation |
---|---|
bin | 10100110000011001… |
… | …01111101000001001 |
3 | 1001202121021222211121 |
4 | 22120030233220021 |
5 | 140310203142413 |
6 | 5041425555241 |
7 | 543100304212 |
oct | 123014575011 |
9 | 31677258747 |
10 | 11143412233 |
11 | 47a91905a8 |
12 | 21abaa5b21 |
13 | 108785ab65 |
14 | 779d62409 |
15 | 45346bb8d |
hex | 29832fa09 |
11143412233 has 8 divisors (see below), whose sum is σ = 11357610696. Its totient is φ = 10929360000.
The previous prime is 11143412227. The next prime is 11143412237. The reversal of 11143412233 is 33221434111.
It can be written as a sum of positive squares in 4 ways, for example, as 1698099264 + 9445312969 = 41208^2 + 97187^2 .
It is a sphenic number, since it is the product of 3 distinct primes.
It is a cyclic number.
It is not a de Polignac number, because 11143412233 - 217 = 11143281161 is a prime.
It is a Duffinian number.
It is a junction number, because it is equal to n+sod(n) for n = 11143412198 and 11143412207.
It is not an unprimeable number, because it can be changed into a prime (11143412237) by changing a digit.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 124023 + ... + 194083.
It is an arithmetic number, because the mean of its divisors is an integer number (1419701337).
Almost surely, 211143412233 is an apocalyptic number.
It is an amenable number.
11143412233 is a deficient number, since it is larger than the sum of its proper divisors (214198463).
11143412233 is an equidigital number, since it uses as much as digits as its factorization.
11143412233 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 73115.
The product of its digits is 1728, while the sum is 25.
Adding to 11143412233 its reverse (33221434111), we get a palindrome (44364846344).
The spelling of 11143412233 in words is "eleven billion, one hundred forty-three million, four hundred twelve thousand, two hundred thirty-three".
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