Base | Representation |
---|---|
bin | 10000001101110100011… |
… | …011111001011110001011 |
3 | 10221112022222010022001122 |
4 | 100031310123321132023 |
5 | 121224142100000021 |
6 | 2211531511505455 |
7 | 143336426500163 |
oct | 20156433713613 |
9 | 3845288108048 |
10 | 1114350000011 |
11 | 39a658584436 |
12 | 15bb7568828b |
13 | 8110ca70341 |
14 | 3bd1324b5a3 |
15 | 1dec06bcbab |
hex | 103746f978b |
1114350000011 has 2 divisors, whose sum is σ = 1114350000012. Its totient is φ = 1114350000010.
The previous prime is 1114349999963. The next prime is 1114350000067. The reversal of 1114350000011 is 1100000534111.
It is a weak prime.
It is an emirp because it is prime and its reverse (1100000534111) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 1114350000011 - 222 = 1114345805707 is a prime.
It is not a weakly prime, because it can be changed into another prime (1114350000091) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 557175000005 + 557175000006.
It is an arithmetic number, because the mean of its divisors is an integer number (557175000006).
Almost surely, 21114350000011 is an apocalyptic number.
1114350000011 is a deficient number, since it is larger than the sum of its proper divisors (1).
1114350000011 is an equidigital number, since it uses as much as digits as its factorization.
1114350000011 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 60, while the sum is 17.
Adding to 1114350000011 its reverse (1100000534111), we get a palindrome (2214350534122).
The spelling of 1114350000011 in words is "one trillion, one hundred fourteen billion, three hundred fifty million, eleven", and thus it is an aban number.
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