Base | Representation |
---|---|
bin | 10100110000011010… |
… | …01110111110011001 |
3 | 1001202121112111222011 |
4 | 22120031032332121 |
5 | 140310221300013 |
6 | 5041432425521 |
7 | 543101350441 |
oct | 123015167631 |
9 | 31677474864 |
10 | 11143540633 |
11 | 47a9269015 |
12 | 21abb482a1 |
13 | 10878a4434 |
14 | 779d97121 |
15 | 453494c3d |
hex | 29834ef99 |
11143540633 has 2 divisors, whose sum is σ = 11143540634. Its totient is φ = 11143540632.
The previous prime is 11143540621. The next prime is 11143540649. The reversal of 11143540633 is 33604534111.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 10361611264 + 781929369 = 101792^2 + 27963^2 .
It is an emirp because it is prime and its reverse (33604534111) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 11143540633 - 225 = 11109986201 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 11143540595 and 11143540604.
It is not a weakly prime, because it can be changed into another prime (11143540673) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5571770316 + 5571770317.
It is an arithmetic number, because the mean of its divisors is an integer number (5571770317).
Almost surely, 211143540633 is an apocalyptic number.
It is an amenable number.
11143540633 is a deficient number, since it is larger than the sum of its proper divisors (1).
11143540633 is an equidigital number, since it uses as much as digits as its factorization.
11143540633 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 12960, while the sum is 31.
The spelling of 11143540633 in words is "eleven billion, one hundred forty-three million, five hundred forty thousand, six hundred thirty-three".
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