Base | Representation |
---|---|
bin | 10000001101110111101… |
… | …010011011111110010001 |
3 | 10221112110202000001021021 |
4 | 100031313222123332101 |
5 | 121224244430033433 |
6 | 2211541124155441 |
7 | 143340654631351 |
oct | 20156752337621 |
9 | 3845422001237 |
10 | 1114404142993 |
11 | 39a6860a48a9 |
12 | 15bb8b838b81 |
13 | 8111b0493cb |
14 | 3bd1a502b61 |
15 | 1dec531522d |
hex | 10377a9bf91 |
1114404142993 has 2 divisors, whose sum is σ = 1114404142994. Its totient is φ = 1114404142992.
The previous prime is 1114404142961. The next prime is 1114404143029. The reversal of 1114404142993 is 3992414044111.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 1077429468049 + 36974674944 = 1037993^2 + 192288^2 .
It is a cyclic number.
It is not a de Polignac number, because 1114404142993 - 25 = 1114404142961 is a prime.
It is not a weakly prime, because it can be changed into another prime (1114404142903) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 557202071496 + 557202071497.
It is an arithmetic number, because the mean of its divisors is an integer number (557202071497).
Almost surely, 21114404142993 is an apocalyptic number.
It is an amenable number.
1114404142993 is a deficient number, since it is larger than the sum of its proper divisors (1).
1114404142993 is an equidigital number, since it uses as much as digits as its factorization.
1114404142993 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 124416, while the sum is 43.
The spelling of 1114404142993 in words is "one trillion, one hundred fourteen billion, four hundred four million, one hundred forty-two thousand, nine hundred ninety-three".
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