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1114412214013 = 7159201744859
BaseRepresentation
bin10000001101111000001…
…001001110011011111101
310221112111022012002121221
4100031320021032123331
5121224304011322023
62211542013153341
7143341113345130
oct20157011163375
93845438162557
101114412214013
1139a68a70776a
1215bb9248b851
138111c913c67
143bd1b604217
151dec5dab85d
hex1037824e6fd

1114412214013 has 4 divisors (see below), whose sum is σ = 1273613958880. Its totient is φ = 955210469148.

The previous prime is 1114412214001. The next prime is 1114412214059. The reversal of 1114412214013 is 3104122144111.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 1114412214013 - 29 = 1114412213501 is a prime.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (1114412214313) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 79600872423 + ... + 79600872436.

It is an arithmetic number, because the mean of its divisors is an integer number (318403489720).

Almost surely, 21114412214013 is an apocalyptic number.

It is an amenable number.

1114412214013 is a deficient number, since it is larger than the sum of its proper divisors (159201744867).

1114412214013 is an equidigital number, since it uses as much as digits as its factorization.

1114412214013 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 159201744866.

The product of its (nonzero) digits is 768, while the sum is 25.

Adding to 1114412214013 its reverse (3104122144111), we get a palindrome (4218534358124).

The spelling of 1114412214013 in words is "one trillion, one hundred fourteen billion, four hundred twelve million, two hundred fourteen thousand, thirteen".

Divisors: 1 7 159201744859 1114412214013