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11144462517113 is a prime number
BaseRepresentation
bin1010001000101100010110…
…1110101100001101111001
31110110101210202100220201012
42202023011232230031321
52430042324401021423
635411410112403305
72230106112260522
oct242130556541571
943411722326635
1011144462517113
113607381612222
1212bba55b46535
1362abc2697903
142a7575713849
15144d5e063078
hexa22c5bac379

11144462517113 has 2 divisors, whose sum is σ = 11144462517114. Its totient is φ = 11144462517112.

The previous prime is 11144462517103. The next prime is 11144462517121. The reversal of 11144462517113 is 31171526444111.

11144462517113 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 9692842368889 + 1451620148224 = 3113333^2 + 1204832^2 .

It is a cyclic number.

It is not a de Polignac number, because 11144462517113 - 218 = 11144462254969 is a prime.

It is not a weakly prime, because it can be changed into another prime (11144462517103) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5572231258556 + 5572231258557.

It is an arithmetic number, because the mean of its divisors is an integer number (5572231258557).

Almost surely, 211144462517113 is an apocalyptic number.

It is an amenable number.

11144462517113 is a deficient number, since it is larger than the sum of its proper divisors (1).

11144462517113 is an equidigital number, since it uses as much as digits as its factorization.

11144462517113 is an evil number, because the sum of its binary digits is even.

The product of its digits is 80640, while the sum is 41.

The spelling of 11144462517113 in words is "eleven trillion, one hundred forty-four billion, four hundred sixty-two million, five hundred seventeen thousand, one hundred thirteen".