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1114450367873 is a prime number
BaseRepresentation
bin10000001101111010011…
…010110001010110000001
310221112120221222111212212
4100031322122301112001
5121224343243232443
62211545455031505
7143342055553643
oct20157232612601
93845527874785
101114450367873
1139a6aa1a7287
1215bba320b595
13811277b23cb
143bd226d6893
151dec93e6618
hex1037a6b1581

1114450367873 has 2 divisors, whose sum is σ = 1114450367874. Its totient is φ = 1114450367872.

The previous prime is 1114450367839. The next prime is 1114450367887. The reversal of 1114450367873 is 3787630544111.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 1099167721744 + 15282646129 = 1048412^2 + 123623^2 .

It is a cyclic number.

It is not a de Polignac number, because 1114450367873 - 28 = 1114450367617 is a prime.

It is not a weakly prime, because it can be changed into another prime (1114450367803) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 557225183936 + 557225183937.

It is an arithmetic number, because the mean of its divisors is an integer number (557225183937).

Almost surely, 21114450367873 is an apocalyptic number.

It is an amenable number.

1114450367873 is a deficient number, since it is larger than the sum of its proper divisors (1).

1114450367873 is an equidigital number, since it uses as much as digits as its factorization.

1114450367873 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 1693440, while the sum is 50.

The spelling of 1114450367873 in words is "one trillion, one hundred fourteen billion, four hundred fifty million, three hundred sixty-seven thousand, eight hundred seventy-three".