Base | Representation |
---|---|
bin | 110011111001100001… |
… | …1101100001010100111 |
3 | 101122200021121220001121 |
4 | 1213303003230022213 |
5 | 3311223203410343 |
6 | 123111135234411 |
7 | 11023612324105 |
oct | 1476303541247 |
9 | 348607556047 |
10 | 111452013223 |
11 | 432a2835141 |
12 | 19725078a07 |
13 | a68228a225 |
14 | 5573d94c75 |
15 | 2d74813aed |
hex | 19f30ec2a7 |
111452013223 has 4 divisors (see below), whose sum is σ = 115047239488. Its totient is φ = 107856786960.
The previous prime is 111452013221. The next prime is 111452013229. The reversal of 111452013223 is 322310254111.
It is a semiprime because it is the product of two primes, and also an emirpimes, since its reverse is a distinct semiprime: 322310254111 = 757 ⋅425773123.
It is a cyclic number.
It is not a de Polignac number, because 111452013223 - 21 = 111452013221 is a prime.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (111452013221) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1797613086 + ... + 1797613147.
It is an arithmetic number, because the mean of its divisors is an integer number (28761809872).
Almost surely, 2111452013223 is an apocalyptic number.
111452013223 is a deficient number, since it is larger than the sum of its proper divisors (3595226265).
111452013223 is an equidigital number, since it uses as much as digits as its factorization.
111452013223 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 3595226264.
The product of its (nonzero) digits is 1440, while the sum is 25.
Adding to 111452013223 its reverse (322310254111), we get a palindrome (433762267334).
The spelling of 111452013223 in words is "one hundred eleven billion, four hundred fifty-two million, thirteen thousand, two hundred twenty-three".
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