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111455421593 is a prime number
BaseRepresentation
bin110011111001101000…
…0101100010010011001
3101122200112001001110112
41213303100230102121
53311230041442333
6123111340254105
711023653311045
oct1476320542231
9348615031415
10111455421593
11432a475297a
1219726241335
13a682bb1709
145574601025
152d74c88948
hex19f342c499

111455421593 has 2 divisors, whose sum is σ = 111455421594. Its totient is φ = 111455421592.

The previous prime is 111455421577. The next prime is 111455421619. The reversal of 111455421593 is 395124554111.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 90810617104 + 20644804489 = 301348^2 + 143683^2 .

It is a cyclic number.

It is not a de Polignac number, because 111455421593 - 24 = 111455421577 is a prime.

It is a super-2 number, since 2×1114554215932 (a number of 23 digits) contains 22 as substring.

It is a self number, because there is not a number n which added to its sum of digits gives 111455421593.

It is not a weakly prime, because it can be changed into another prime (111455421893) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 55727710796 + 55727710797.

It is an arithmetic number, because the mean of its divisors is an integer number (55727710797).

Almost surely, 2111455421593 is an apocalyptic number.

It is an amenable number.

111455421593 is a deficient number, since it is larger than the sum of its proper divisors (1).

111455421593 is an equidigital number, since it uses as much as digits as its factorization.

111455421593 is an evil number, because the sum of its binary digits is even.

The product of its digits is 108000, while the sum is 41.

The spelling of 111455421593 in words is "one hundred eleven billion, four hundred fifty-five million, four hundred twenty-one thousand, five hundred ninety-three".