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1114554300242 = 2557277150121
BaseRepresentation
bin10000001110000000100…
…111001111011101010010
310221112212012112211021212
4100032000213033131102
5121230101400101432
62212004050420122
7143344460144525
oct20160047173522
93845765484255
101114554300242
1139a7529341a9
12160011b91642
13811431a1a56
143bd3242cbbc
151ded35c62b2
hex103809cf752

1114554300242 has 4 divisors (see below), whose sum is σ = 1671831450366. Its totient is φ = 557277150120.

The previous prime is 1114554300241. The next prime is 1114554300253. The reversal of 1114554300242 is 2420034554111.

It is a semiprime because it is the product of two primes.

It can be written as a sum of positive squares in only one way, i.e., 893023110001 + 221531190241 = 944999^2 + 470671^2 .

It is a junction number, because it is equal to n+sod(n) for n = 1114554300199 and 1114554300208.

It is not an unprimeable number, because it can be changed into a prime (1114554300241) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 278638575059 + ... + 278638575062.

Almost surely, 21114554300242 is an apocalyptic number.

1114554300242 is a deficient number, since it is larger than the sum of its proper divisors (557277150124).

1114554300242 is an equidigital number, since it uses as much as digits as its factorization.

1114554300242 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 557277150123.

The product of its (nonzero) digits is 19200, while the sum is 32.

Adding to 1114554300242 its reverse (2420034554111), we get a palindrome (3534588854353).

The spelling of 1114554300242 in words is "one trillion, one hundred fourteen billion, five hundred fifty-four million, three hundred thousand, two hundred forty-two".

Divisors: 1 2 557277150121 1114554300242