Base | Representation |
---|---|
bin | 10100110000110111… |
… | …11000110001011011 |
3 | 1001202212202200010111 |
4 | 22120123320301123 |
5 | 140312212204401 |
6 | 5042051025151 |
7 | 543146116354 |
oct | 123033706133 |
9 | 31685680114 |
10 | 11147381851 |
11 | 4800451a81 |
12 | 21b129b1b7 |
13 | 108861a948 |
14 | 77a6b6d2b |
15 | 4539a2e51 |
hex | 2986f8c5b |
11147381851 has 2 divisors, whose sum is σ = 11147381852. Its totient is φ = 11147381850.
The previous prime is 11147381837. The next prime is 11147381857. The reversal of 11147381851 is 15818374111.
It is a strong prime.
It is an emirp because it is prime and its reverse (15818374111) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 11147381851 - 213 = 11147373659 is a prime.
It is not a weakly prime, because it can be changed into another prime (11147381857) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5573690925 + 5573690926.
It is an arithmetic number, because the mean of its divisors is an integer number (5573690926).
Almost surely, 211147381851 is an apocalyptic number.
11147381851 is a deficient number, since it is larger than the sum of its proper divisors (1).
11147381851 is an equidigital number, since it uses as much as digits as its factorization.
11147381851 is an evil number, because the sum of its binary digits is even.
The product of its digits is 26880, while the sum is 40.
The spelling of 11147381851 in words is "eleven billion, one hundred forty-seven million, three hundred eighty-one thousand, eight hundred fifty-one".
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