Base | Representation |
---|---|
bin | 10000001110011111011… |
… | …110101101011011011001 |
3 | 10221121012021222200202122 |
4 | 100032133132231123121 |
5 | 121232131433014101 |
6 | 2212131310111025 |
7 | 143363345644256 |
oct | 20163736553331 |
9 | 3847167880678 |
10 | 1115072157401 |
11 | 39a999187a24 |
12 | 1601374ab475 |
13 | 811c6569ac7 |
14 | 3bd8111242d |
15 | 1e013cba51b |
hex | 1039f7ad6d9 |
1115072157401 has 2 divisors, whose sum is σ = 1115072157402. Its totient is φ = 1115072157400.
The previous prime is 1115072157389. The next prime is 1115072157431. The reversal of 1115072157401 is 1047512705111.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 922790784400 + 192281373001 = 960620^2 + 438499^2 .
It is a cyclic number.
It is not a de Polignac number, because 1115072157401 - 218 = 1115071895257 is a prime.
It is not a weakly prime, because it can be changed into another prime (1115072157431) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 557536078700 + 557536078701.
It is an arithmetic number, because the mean of its divisors is an integer number (557536078701).
Almost surely, 21115072157401 is an apocalyptic number.
It is an amenable number.
1115072157401 is a deficient number, since it is larger than the sum of its proper divisors (1).
1115072157401 is an equidigital number, since it uses as much as digits as its factorization.
1115072157401 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 9800, while the sum is 35.
The spelling of 1115072157401 in words is "one trillion, one hundred fifteen billion, seventy-two million, one hundred fifty-seven thousand, four hundred one".
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