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111513441103 = 164176792559
BaseRepresentation
bin110011111011010111…
…0000001001101001111
3101122211120012202021021
41213312232001031033
53311334420103403
6123121212015011
711025256416121
oct1476656011517
9348746182237
10111513441103
1143324480889
1219741761467
13a691c1709c
14557c1c5211
152d79de98bd
hex19f6b8134f

111513441103 has 4 divisors (see below), whose sum is σ = 111520250080. Its totient is φ = 111506632128.

The previous prime is 111513441097. The next prime is 111513441121. The reversal of 111513441103 is 301144315111.

It is a semiprime because it is the product of two primes, and also an emirpimes, since its reverse is a distinct semiprime: 301144315111 = 614936792051.

It is a cyclic number.

It is not a de Polignac number, because 111513441103 - 25 = 111513441071 is a prime.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (111513447103) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 3379863 + ... + 3412696.

It is an arithmetic number, because the mean of its divisors is an integer number (27880062520).

Almost surely, 2111513441103 is an apocalyptic number.

111513441103 is a deficient number, since it is larger than the sum of its proper divisors (6808977).

111513441103 is an equidigital number, since it uses as much as digits as its factorization.

111513441103 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 6808976.

The product of its (nonzero) digits is 720, while the sum is 25.

Adding to 111513441103 its reverse (301144315111), we get a palindrome (412657756214).

The spelling of 111513441103 in words is "one hundred eleven billion, five hundred thirteen million, four hundred forty-one thousand, one hundred three".

Divisors: 1 16417 6792559 111513441103