11153106514441 has 2 divisors, whose sum is σ = 11153106514442. Its totient is φ = 11153106514440.

The previous prime is 11153106514339. The next prime is 11153106514477. The reversal of 11153106514441 is 14441560135111.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 9557990560000 + 1595115954441 = 3091600^2 + 1262979^2 .

It is a cyclic number.

It is not a de Polignac number, because 11153106514441 - 2⁹ = 11153106513929 is a prime.

It is a self number, because there is not a number n which added to its sum of digits gives 11153106514441.

It is not a weakly prime, because it can be changed into another prime (11153106511441) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5576553257220 + 5576553257221.

It is an arithmetic number, because the mean of its divisors is an integer number (5576553257221).

Almost surely, 2^{11153106514441} is an apocalyptic number.

It is an amenable number.

11153106514441 is a deficient number, since it is larger than the sum of its proper divisors (1).

11153106514441 is an equidigital number, since it uses as much as digits as its factorization.

11153106514441 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 28800, while the sum is 37.

Adding to 11153106514441 its reverse (14441560135111), we get a palindrome (25594666649552).

The spelling of 11153106514441 in words is "eleven trillion, one hundred fifty-three billion, one hundred six million, five hundred fourteen thousand, four hundred forty-one".