Base | Representation |
---|---|
bin | 10000001110101111100… |
… | …000011101100011110001 |
3 | 10221121220000221222000020 |
4 | 100032233200131203301 |
5 | 121233204302132040 |
6 | 2212214113314053 |
7 | 143403122343045 |
oct | 20165740354361 |
9 | 3847800858006 |
10 | 1115341052145 |
11 | 3a0016a46591 |
12 | 1601b1565929 |
13 | 8123a196818 |
14 | 3bda8b0a025 |
15 | 1e02c6d2cd0 |
hex | 103af81d8f1 |
1115341052145 has 32 divisors (see below), whose sum is σ = 1900833516288. Its totient is φ = 556505008128.
The previous prime is 1115341052117. The next prime is 1115341052171. The reversal of 1115341052145 is 5412501435111.
It is not a de Polignac number, because 1115341052145 - 225 = 1115307497713 is a prime.
It is a super-3 number, since 3×11153410521453 (a number of 37 digits) contains 333 as substring.
It is an unprimeable number.
It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 13052884 + ... + 13138053.
It is an arithmetic number, because the mean of its divisors is an integer number (59401047384).
Almost surely, 21115341052145 is an apocalyptic number.
1115341052145 is a gapful number since it is divisible by the number (15) formed by its first and last digit.
It is an amenable number.
1115341052145 is a deficient number, since it is larger than the sum of its proper divisors (785492464143).
1115341052145 is a wasteful number, since it uses less digits than its factorization.
1115341052145 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 26191129.
The product of its (nonzero) digits is 12000, while the sum is 33.
Adding to 1115341052145 its reverse (5412501435111), we get a palindrome (6527842487256).
The spelling of 1115341052145 in words is "one trillion, one hundred fifteen billion, three hundred forty-one million, fifty-two thousand, one hundred forty-five".
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