Base | Representation |
---|---|
bin | 10100110001101010… |
… | …01000100001111001 |
3 | 1001210100012220111212 |
4 | 22120311020201321 |
5 | 140320410444433 |
6 | 5042444532505 |
7 | 543256302263 |
oct | 123065104171 |
9 | 31710186455 |
10 | 11153999993 |
11 | 4804162314 |
12 | 21b3551135 |
13 | 1089ac70c6 |
14 | 77b51ab33 |
15 | 45435dd48 |
hex | 298d48879 |
11153999993 has 2 divisors, whose sum is σ = 11153999994. Its totient is φ = 11153999992.
The previous prime is 11153999977. The next prime is 11154000001. The reversal of 11153999993 is 39999935111.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 9731427904 + 1422572089 = 98648^2 + 37717^2 .
It is an emirp because it is prime and its reverse (39999935111) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 11153999993 - 24 = 11153999977 is a prime.
It is not a weakly prime, because it can be changed into another prime (11153999963) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5576999996 + 5576999997.
It is an arithmetic number, because the mean of its divisors is an integer number (5576999997).
Almost surely, 211153999993 is an apocalyptic number.
It is an amenable number.
11153999993 is a deficient number, since it is larger than the sum of its proper divisors (1).
11153999993 is an equidigital number, since it uses as much as digits as its factorization.
11153999993 is an odious number, because the sum of its binary digits is odd.
The product of its digits is 2657205, while the sum is 59.
The spelling of 11153999993 in words is "eleven billion, one hundred fifty-three million, nine hundred ninety-nine thousand, nine hundred ninety-three".
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