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11156077133251 is a prime number
BaseRepresentation
bin1010001001010111101000…
…0000111011110111000011
31110111111210012022112210021
42202111322000323313003
52430240121221231001
635421010414114311
72230666664006251
oct242257200736703
943444705275707
1011156077133251
1136112a1781236
1213021577ab997
1362c023a3783b
142a7d580935d1
151452dda5aba1
hexa257a03bdc3

11156077133251 has 2 divisors, whose sum is σ = 11156077133252. Its totient is φ = 11156077133250.

The previous prime is 11156077133221. The next prime is 11156077133329. The reversal of 11156077133251 is 15233177065111.

11156077133251 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a weak prime.

It is an emirp because it is prime and its reverse (15233177065111) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 11156077133251 - 225 = 11156043578819 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 11156077133198 and 11156077133207.

It is not a weakly prime, because it can be changed into another prime (11156077133221) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5578038566625 + 5578038566626.

It is an arithmetic number, because the mean of its divisors is an integer number (5578038566626).

Almost surely, 211156077133251 is an apocalyptic number.

11156077133251 is a deficient number, since it is larger than the sum of its proper divisors (1).

11156077133251 is an equidigital number, since it uses as much as digits as its factorization.

11156077133251 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 132300, while the sum is 43.

The spelling of 11156077133251 in words is "eleven trillion, one hundred fifty-six billion, seventy-seven million, one hundred thirty-three thousand, two hundred fifty-one".