Base | Representation |
---|---|
bin | 10000001111100110011… |
… | …011100001100110001011 |
3 | 10221201021020211121110221 |
4 | 100033212123201212023 |
5 | 121242101200123333 |
6 | 2212445351250511 |
7 | 143435011511053 |
oct | 20174633414613 |
9 | 3851236747427 |
10 | 1116262504843 |
11 | 3a044a0a0642 |
12 | 16040a079a37 |
13 | 813560618c5 |
14 | 3c05524c563 |
15 | 1e08354ad2d |
hex | 103e66e198b |
1116262504843 has 2 divisors, whose sum is σ = 1116262504844. Its totient is φ = 1116262504842.
The previous prime is 1116262504829. The next prime is 1116262504853. The reversal of 1116262504843 is 3484052626111.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 1116262504843 - 217 = 1116262373771 is a prime.
It is a self number, because there is not a number n which added to its sum of digits gives 1116262504843.
It is not a weakly prime, because it can be changed into another prime (1116262504823) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 558131252421 + 558131252422.
It is an arithmetic number, because the mean of its divisors is an integer number (558131252422).
Almost surely, 21116262504843 is an apocalyptic number.
1116262504843 is a deficient number, since it is larger than the sum of its proper divisors (1).
1116262504843 is an equidigital number, since it uses as much as digits as its factorization.
1116262504843 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 276480, while the sum is 43.
The spelling of 1116262504843 in words is "one trillion, one hundred sixteen billion, two hundred sixty-two million, five hundred four thousand, eight hundred forty-three".
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