Base | Representation |
---|---|
bin | 1010001001110001011011… |
… | …1100110001101011110011 |
3 | 1110112011200000101022220101 |
4 | 2202130112330301223303 |
5 | 2430343313242030303 |
6 | 35424114055053231 |
7 | 2231333446124302 |
oct | 242342674615363 |
9 | 43464600338811 |
10 | 11163005033203 |
11 | 361422735aa91 |
12 | 130356b971217 |
13 | 62c88911811a |
14 | 2a8414202439 |
15 | 145596d81d1d |
hex | a2716f31af3 |
11163005033203 has 2 divisors, whose sum is σ = 11163005033204. Its totient is φ = 11163005033202.
The previous prime is 11163005033197. The next prime is 11163005033233. The reversal of 11163005033203 is 30233050036111.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 11163005033203 - 29 = 11163005032691 is a prime.
It is a super-2 number, since 2×111630050332032 (a number of 27 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (11163005033233) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5581502516601 + 5581502516602.
It is an arithmetic number, because the mean of its divisors is an integer number (5581502516602).
Almost surely, 211163005033203 is an apocalyptic number.
11163005033203 is a deficient number, since it is larger than the sum of its proper divisors (1).
11163005033203 is an equidigital number, since it uses as much as digits as its factorization.
11163005033203 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 4860, while the sum is 28.
Adding to 11163005033203 its reverse (30233050036111), we get a palindrome (41396055069314).
The spelling of 11163005033203 in words is "eleven trillion, one hundred sixty-three billion, five million, thirty-three thousand, two hundred three".
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