Base | Representation |
---|---|
bin | 110011111111100111… |
… | …0011000000101010001 |
3 | 101200012111201122220201 |
4 | 1213333032120011101 |
5 | 3312132433004022 |
6 | 123143310335201 |
7 | 11031641353162 |
oct | 1477716300521 |
9 | 350174648821 |
10 | 111656141137 |
11 | 43397a874a2 |
12 | 197814ba501 |
13 | a6b565b388 |
14 | 559312d769 |
15 | 2d876d6127 |
hex | 19ff398151 |
111656141137 has 2 divisors, whose sum is σ = 111656141138. Its totient is φ = 111656141136.
The previous prime is 111656141099. The next prime is 111656141147. The reversal of 111656141137 is 731141656111.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 57697961616 + 53958179521 = 240204^2 + 232289^2 .
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-111656141137 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 111656141096 and 111656141105.
It is not a weakly prime, because it can be changed into another prime (111656141147) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 55828070568 + 55828070569.
It is an arithmetic number, because the mean of its divisors is an integer number (55828070569).
Almost surely, 2111656141137 is an apocalyptic number.
It is an amenable number.
111656141137 is a deficient number, since it is larger than the sum of its proper divisors (1).
111656141137 is an equidigital number, since it uses as much as digits as its factorization.
111656141137 is an evil number, because the sum of its binary digits is even.
The product of its digits is 15120, while the sum is 37.
Adding to 111656141137 its reverse (731141656111), we get a palindrome (842797797248).
The spelling of 111656141137 in words is "one hundred eleven billion, six hundred fifty-six million, one hundred forty-one thousand, one hundred thirty-seven".
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