Base | Representation |
---|---|
bin | 10000010000010010100… |
… | …110010111001010000001 |
3 | 10221210011220020020221212 |
4 | 100100102212113022001 |
5 | 121300110401340134 |
6 | 2213051102255505 |
7 | 143462250313463 |
oct | 20202246271201 |
9 | 3853156206855 |
10 | 1117003543169 |
11 | 3a079a41a708 |
12 | 160596287595 |
13 | 8144373c317 |
14 | 3c0c582a133 |
15 | 1e0c8627bce |
hex | 10412997281 |
1117003543169 has 2 divisors, whose sum is σ = 1117003543170. Its totient is φ = 1117003543168.
The previous prime is 1117003543087. The next prime is 1117003543199. The reversal of 1117003543169 is 9613453007111.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 1107377382400 + 9626160769 = 1052320^2 + 98113^2 .
It is a cyclic number.
It is not a de Polignac number, because 1117003543169 - 212 = 1117003539073 is a prime.
It is a super-2 number, since 2×11170035431692 (a number of 25 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (1117003543199) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 558501771584 + 558501771585.
It is an arithmetic number, because the mean of its divisors is an integer number (558501771585).
Almost surely, 21117003543169 is an apocalyptic number.
It is an amenable number.
1117003543169 is a deficient number, since it is larger than the sum of its proper divisors (1).
1117003543169 is an equidigital number, since it uses as much as digits as its factorization.
1117003543169 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 68040, while the sum is 41.
The spelling of 1117003543169 in words is "one trillion, one hundred seventeen billion, three million, five hundred forty-three thousand, one hundred sixty-nine".
• e-mail: info -at- numbersaplenty.com • Privacy notice • done in 0.067 sec. • engine limits •