Base | Representation |
---|---|
bin | 10000010000101001101… |
… | …010010111001011011011 |
3 | 10221211011212022001202212 |
4 | 100100221222113023123 |
5 | 121301403424432203 |
6 | 2213153323345335 |
7 | 143504656156601 |
oct | 20205152271333 |
9 | 3854155261685 |
10 | 1117390467803 |
11 | 3a0978874935 |
12 | 16068398224b |
13 | 814a59532cc |
14 | 3c120d89871 |
15 | 1e0ec5a71d8 |
hex | 10429a972db |
1117390467803 has 2 divisors, whose sum is σ = 1117390467804. Its totient is φ = 1117390467802.
The previous prime is 1117390467797. The next prime is 1117390467827. The reversal of 1117390467803 is 3087640937111.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 1117390467803 - 28 = 1117390467547 is a prime.
It is a super-2 number, since 2×11173904678032 (a number of 25 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (1117390467103) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 558695233901 + 558695233902.
It is an arithmetic number, because the mean of its divisors is an integer number (558695233902).
Almost surely, 21117390467803 is an apocalyptic number.
1117390467803 is a deficient number, since it is larger than the sum of its proper divisors (1).
1117390467803 is an equidigital number, since it uses as much as digits as its factorization.
1117390467803 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 762048, while the sum is 50.
The spelling of 1117390467803 in words is "one trillion, one hundred seventeen billion, three hundred ninety million, four hundred sixty-seven thousand, eight hundred three".
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