Base | Representation |
---|---|
bin | 110100000011010010… |
… | …0111010101101010011 |
3 | 101200112002211110121221 |
4 | 1220012210322231103 |
5 | 3312411022200033 |
6 | 123203434225511 |
7 | 11034666664552 |
oct | 1500644725523 |
9 | 350462743557 |
10 | 111779490643 |
11 | 43450676837 |
12 | 197b6885297 |
13 | a705088a52 |
14 | 55a567bd99 |
15 | 2d9344e12d |
hex | 1a0693ab53 |
111779490643 has 2 divisors, whose sum is σ = 111779490644. Its totient is φ = 111779490642.
The previous prime is 111779490611. The next prime is 111779490671. The reversal of 111779490643 is 346094977111.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 111779490643 - 25 = 111779490611 is a prime.
It is not a weakly prime, because it can be changed into another prime (111779490943) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 55889745321 + 55889745322.
It is an arithmetic number, because the mean of its divisors is an integer number (55889745322).
Almost surely, 2111779490643 is an apocalyptic number.
111779490643 is a deficient number, since it is larger than the sum of its proper divisors (1).
111779490643 is an equidigital number, since it uses as much as digits as its factorization.
111779490643 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 1143072, while the sum is 52.
The spelling of 111779490643 in words is "one hundred eleven billion, seven hundred seventy-nine million, four hundred ninety thousand, six hundred forty-three".
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