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11200000120073 is a prime number
BaseRepresentation
bin1010001011111011010000…
…0001110101010100001001
31110122201011021011110111222
42202332310001311110021
52432000100012320243
635453113052131425
72234113305150362
oct242766401652411
943581137143458
1011200000120073
1136289910a2346
12130a775466b75
13633203785a7b
142aa123688b69
1514650eb54168
hexa2fb4075509

11200000120073 has 2 divisors, whose sum is σ = 11200000120074. Its totient is φ = 11200000120072.

The previous prime is 11200000120037. The next prime is 11200000120079. The reversal of 11200000120073 is 37002100000211.

Together with previous prime (11200000120037) it forms an Ormiston pair, because they use the same digits, order apart.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 6133012626064 + 5066987494009 = 2476492^2 + 2250997^2 .

It is an emirp because it is prime and its reverse (37002100000211) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 11200000120073 - 212 = 11200000115977 is a prime.

It is not a weakly prime, because it can be changed into another prime (11200000120079) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5600000060036 + 5600000060037.

It is an arithmetic number, because the mean of its divisors is an integer number (5600000060037).

Almost surely, 211200000120073 is an apocalyptic number.

It is an amenable number.

11200000120073 is a deficient number, since it is larger than the sum of its proper divisors (1).

11200000120073 is an equidigital number, since it uses as much as digits as its factorization.

11200000120073 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 84, while the sum is 17.

Adding to 11200000120073 its reverse (37002100000211), we get a palindrome (48202100120284).

The spelling of 11200000120073 in words is "eleven trillion, two hundred billion, one hundred twenty thousand, seventy-three".