11200000125121 has 2 divisors, whose sum is σ = 11200000125122. Its totient is φ = 11200000125120.

The previous prime is 11200000125113. The next prime is 11200000125133. The reversal of 11200000125121 is 12152100000211.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 6209869625521 + 4990130499600 = 2491961^2 + 2233860^2 .

It is a cyclic number.

It is not a de Polignac number, because 11200000125121 - 2³ = 11200000125113 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 11200000125095 and 11200000125104.

It is not a weakly prime, because it can be changed into another prime (11200000105121) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5600000062560 + 5600000062561.

It is an arithmetic number, because the mean of its divisors is an integer number (5600000062561).

Almost surely, 2^{11200000125121} is an apocalyptic number.

It is an amenable number.

11200000125121 is a deficient number, since it is larger than the sum of its proper divisors (1).

11200000125121 is an equidigital number, since it uses as much as digits as its factorization.

11200000125121 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 40, while the sum is 16.

Adding to 11200000125121 its reverse (12152100000211), we get a palindrome (23352100125332).

The spelling of 11200000125121 in words is "eleven trillion, two hundred billion, one hundred twenty-five thousand, one hundred twenty-one".