Search a number
-
+
11200001120137 is a prime number
BaseRepresentation
bin1010001011111011010000…
…0101101001011110001001
31110122201011100001021100101
42202332310011221132021
52432000100241321022
635453113125405401
72234113316514124
oct242766405513611
943581140037311
1011200001120137
113628991715745
12130a775869861
13633203a4601b
142aa1238693bb
1514650eca0627
hexa2fb4169789

11200001120137 has 2 divisors, whose sum is σ = 11200001120138. Its totient is φ = 11200001120136.

The previous prime is 11200001120111. The next prime is 11200001120177. The reversal of 11200001120137 is 73102110000211.

11200001120137 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 10840398210576 + 359602909561 = 3292476^2 + 599669^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-11200001120137 is a prime.

It is not a weakly prime, because it can be changed into another prime (11200001120177) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5600000560068 + 5600000560069.

It is an arithmetic number, because the mean of its divisors is an integer number (5600000560069).

Almost surely, 211200001120137 is an apocalyptic number.

It is an amenable number.

11200001120137 is a deficient number, since it is larger than the sum of its proper divisors (1).

11200001120137 is an equidigital number, since it uses as much as digits as its factorization.

11200001120137 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 84, while the sum is 19.

Adding to 11200001120137 its reverse (73102110000211), we get a palindrome (84302111120348).

The spelling of 11200001120137 in words is "eleven trillion, two hundred billion, one million, one hundred twenty thousand, one hundred thirty-seven".