Base | Representation |
---|---|
bin | 10000010011000101010… |
… | …100100110111110010011 |
3 | 10222001220212101012120222 |
4 | 100103011110212332103 |
5 | 121322231003323102 |
6 | 2214304414023255 |
7 | 143626460005334 |
oct | 20230524467623 |
9 | 3861825335528 |
10 | 1120002011027 |
11 | 3a1a98a33a19 |
12 | 1610924a7b2b |
13 | 81800a08363 |
14 | 3c2cbb5428b |
15 | 1e2019b7aa2 |
hex | 104c5526f93 |
1120002011027 has 2 divisors, whose sum is σ = 1120002011028. Its totient is φ = 1120002011026.
The previous prime is 1120002010969. The next prime is 1120002011173. The reversal of 1120002011027 is 7201102000211.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 1120002011027 - 210 = 1120002010003 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 1120002010996 and 1120002011014.
It is not a weakly prime, because it can be changed into another prime (1120002011827) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 560001005513 + 560001005514.
It is an arithmetic number, because the mean of its divisors is an integer number (560001005514).
Almost surely, 21120002011027 is an apocalyptic number.
1120002011027 is a deficient number, since it is larger than the sum of its proper divisors (1).
1120002011027 is an equidigital number, since it uses as much as digits as its factorization.
1120002011027 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 56, while the sum is 17.
Adding to 1120002011027 its reverse (7201102000211), we get a palindrome (8321104011238).
The spelling of 1120002011027 in words is "one trillion, one hundred twenty billion, two million, eleven thousand, twenty-seven".
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