Base | Representation |
---|---|
bin | 10000010011000110100… |
… | …001101011000110001011 |
3 | 10222001222021101120111022 |
4 | 100103012201223012023 |
5 | 121322301141304003 |
6 | 2214310415023055 |
7 | 143630123505251 |
oct | 20230641530613 |
9 | 3861867346438 |
10 | 1120022213003 |
11 | 3a1aa9381a71 |
12 | 16109920aa8b |
13 | 81804c5c6a5 |
14 | 3c2d06d25d1 |
15 | 1e203658738 |
hex | 104c686b18b |
1120022213003 has 2 divisors, whose sum is σ = 1120022213004. Its totient is φ = 1120022213002.
The previous prime is 1120022212963. The next prime is 1120022213053. The reversal of 1120022213003 is 3003122200211.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 1120022213003 - 222 = 1120018018699 is a prime.
It is not a weakly prime, because it can be changed into another prime (1120022213053) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (17) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 560011106501 + 560011106502.
It is an arithmetic number, because the mean of its divisors is an integer number (560011106502).
Almost surely, 21120022213003 is an apocalyptic number.
1120022213003 is a deficient number, since it is larger than the sum of its proper divisors (1).
1120022213003 is an equidigital number, since it uses as much as digits as its factorization.
1120022213003 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 144, while the sum is 17.
Adding to 1120022213003 its reverse (3003122200211), we get a palindrome (4123144413214).
The spelling of 1120022213003 in words is "one trillion, one hundred twenty billion, twenty-two million, two hundred thirteen thousand, three".
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