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112003212012000 = 25353173517156109
BaseRepresentation
bin11001011101110111000111…
…101010100110100111100000
3112200120101212102100202012120
4121131313013222212213200
5104140030034233341000
61034113322033224240
732406652001624241
oct3135670752464740
9480511772322176
10112003212012000
1132762328299151
121068ab81102080
134a65b1c11b93a
141d92dad224cc8
15ce36d96b26a0
hex65ddc7aa69e0

112003212012000 has 384 divisors, whose sum is σ = 388619154967680. Its totient is φ = 28102437273600.

The previous prime is 112003212011953. The next prime is 112003212012023. The reversal of 112003212012000 is 210212300211.

112003212012000 is digitally balanced in base 3, because in such base it contains all the possibile digits an equal number of times.

It is a Harshad number since it is a multiple of its sum of digits (15).

It is a congruent number.

It is an unprimeable number.

It is a polite number, since it can be written in 63 ways as a sum of consecutive naturals, for example, 717389946 + ... + 717546054.

It is an arithmetic number, because the mean of its divisors is an integer number (1012029049395).

Almost surely, 2112003212012000 is an apocalyptic number.

112003212012000 is a gapful number since it is divisible by the number (10) formed by its first and last digit.

It is an amenable number.

It is a practical number, because each smaller number is the sum of distinct divisors of 112003212012000, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (194309577483840).

112003212012000 is an abundant number, since it is smaller than the sum of its proper divisors (276615942955680).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

112003212012000 is a wasteful number, since it uses less digits than its factorization.

112003212012000 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 159671 (or 159653 counting only the distinct ones).

The product of its (nonzero) digits is 48, while the sum is 15.

Adding to 112003212012000 its reverse (210212300211), we get a palindrome (112213424312211).

The spelling of 112003212012000 in words is "one hundred twelve trillion, three billion, two hundred twelve million, twelve thousand".