Base | Representation |
---|---|
bin | 10000010011001011001… |
… | …010011111000011010001 |
3 | 10222002011200210121012222 |
4 | 100103023022133003101 |
5 | 121322431101123213 |
6 | 2214322234430425 |
7 | 143632060040132 |
oct | 20231312370321 |
9 | 3862150717188 |
10 | 1120100020433 |
11 | 3a2039295929 |
12 | 1610bb292415 |
13 | 81818102aa4 |
14 | 3c2dab87c89 |
15 | 1e20a3c7808 |
hex | 104cb29f0d1 |
1120100020433 has 2 divisors, whose sum is σ = 1120100020434. Its totient is φ = 1120100020432.
The previous prime is 1120100020423. The next prime is 1120100020441. The reversal of 1120100020433 is 3340200010211.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 1021934984464 + 98165035969 = 1010908^2 + 313313^2 .
It is a cyclic number.
It is not a de Polignac number, because 1120100020433 - 212 = 1120100016337 is a prime.
It is not a weakly prime, because it can be changed into another prime (1120100020423) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 560050010216 + 560050010217.
It is an arithmetic number, because the mean of its divisors is an integer number (560050010217).
Almost surely, 21120100020433 is an apocalyptic number.
It is an amenable number.
1120100020433 is a deficient number, since it is larger than the sum of its proper divisors (1).
1120100020433 is an equidigital number, since it uses as much as digits as its factorization.
1120100020433 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 144, while the sum is 17.
Adding to 1120100020433 its reverse (3340200010211), we get a palindrome (4460300030644).
The spelling of 1120100020433 in words is "one trillion, one hundred twenty billion, one hundred million, twenty thousand, four hundred thirty-three".
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