Base | Representation |
---|---|
bin | 11001011101111110011000… |
… | …011110010111110010111011 |
3 | 112200121010222220001022011212 |
4 | 121131332120132113302323 |
5 | 104140142022103223003 |
6 | 1034121051523513335 |
7 | 32410346152336301 |
oct | 3135763036276273 |
9 | 480533886038155 |
10 | 112011010211003 |
11 | 3276566a163512 |
12 | 1069059882884b |
13 | 4a667928c6a87 |
14 | 1d9350cb9c271 |
15 | ce39e40e9dd8 |
hex | 65df98797cbb |
112011010211003 has 2 divisors, whose sum is σ = 112011010211004. Its totient is φ = 112011010211002.
The previous prime is 112011010210961. The next prime is 112011010211029. The reversal of 112011010211003 is 300112010110211.
It is a strong prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-112011010211003 is a prime.
It is not a weakly prime, because it can be changed into another prime (112011010241003) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 56005505105501 + 56005505105502.
It is an arithmetic number, because the mean of its divisors is an integer number (56005505105502).
Almost surely, 2112011010211003 is an apocalyptic number.
112011010211003 is a deficient number, since it is larger than the sum of its proper divisors (1).
112011010211003 is an equidigital number, since it uses as much as digits as its factorization.
112011010211003 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 12, while the sum is 14.
Adding to 112011010211003 its reverse (300112010110211), we get a palindrome (412123020321214).
The spelling of 112011010211003 in words is "one hundred twelve trillion, eleven billion, ten million, two hundred eleven thousand, three".
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